Question

a Tower is 50m high when the sun altitude is 45 degrees then what will be the length of its shadow

Answer 1

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Answer 2

Answer:

50 m

Step-by-step explanation:

Refer the attached figure

Height of the tower i. AB = 50m

A Tower is 50m high when the sun altitude is 45 degrees i.e. ∠ACB = 45°

Now we are supposed to find the length of the tower i.e. BC

So, we will use trigonometric ratio.

$Tan\theta = \frac{Perpendicular}{Base}$

$Tan45^{\circ} = \frac{AB}{BC}$

$1 = \frac{50}{BC}$

$50=BC$

Hence the length of the shadow is 50 m.