Question

A tower is 64m. A man is standing at a distance of 36m from the tower observs the top of the tower with the angle of elevation 60°. Find the height of the man.​

Answer 1

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Answer 2

Here's Ur answer,

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Solution :-

Given that ,

Height of Tower is 64m

A man is 36m far from tower and he see on top of tower making angle of elevation 60°.

Now ,

Let the height of man be X .

DE = BC = X

Now ,

AC = AB+BC

64 = AB + X

AB = 64-x.....(I)

In ∆ ABD,

$tan {60}^{o} = \frac{ab}{bd}$

$\sqrt{3} = \frac{64 - x}{36}$

$36 \sqrt{3} = 64 - x$

$x = 64 - 36 \sqrt{3}$

Now , value of √3 is 1.73.

So ,

$x = 64 - 36 \times 1.73$

$x = 64 - 62.28$

$x = 1.72$

So , height of man is 1.72m (approx )

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