Question

a tower is of height 100 meters and a boy observes the top of the tower from a point which is 100 meters away from its foot then the angle of elevation is
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Answer 1

Answer:

Sorry

Step-by-step explanation:

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Answer 2

Given:-

height, h =AB = 100m

distance from foot, d= BC = 100m

To find:-

The angle of elevation (theta)

Proof:-

let the angle be "theta"

then

$tan \: {\theta} \: = \frac{AB}{BC}$

$tan \: { \theta} = \frac{100}{100}$

$tan{\theta} = 1$

At ${ \theta} = 45{\degree}$ {$tan{\theta}=1$}

${\boxed{Angle \: of \: elevation =45{ \degree}}}$