A tower of height 100 m casts a shadow of 100√3 m find the angle of sunn
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Draw a right triangle ABC with B=90 degree.
Height of the shadow = perpendicular,AB=100cm
Shadow height = base of the triangle,BC=100√3cm
Now,
Angle of sun is A
=>tan A = BC/AB=100√3/100=√3
=>tan A=Tan60
=>A=60
Height of the shadow = perpendicular,AB=100cm
Shadow height = base of the triangle,BC=100√3cm
Now,
Angle of sun is A
=>tan A = BC/AB=100√3/100=√3
=>tan A=Tan60
=>A=60
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