Question

A tower stand vertically on the ground. From a point on the ground 20 m away from the foot of the tower, the angle of elevation of the top of the tower is 60°. What is the height of the tower?

Answer 1

Step-by-step explanation:

Here, AB is the height of a tower.

⇒ CB=20m

⇒ Now, tan60° = CB/AB

⇒√3 = AB /20

∴ AB=20 √3m

∴ Height of a tower is 20 √3 m.

Answer 2

Answer:

The height of the tower is 20√3 m.  

Step-by-step explanation:

GIVEN:

Distance between point on the ground and foot of tower , BC = 20 m  

Angle of elevation of the top of the tower, ∠ACB = 60°

Let AB =  h m be the height of the tower

In right angle triangle, ∆ABC ,

tan C = AB/BC = P/ H

√3 = h/20

h = 20√3

AB = 20√3 m

Hence , the height of the tower is 20√3 m.