Math, asked by AkiraKrinsten14, 6 months ago

Find the area of the question.

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Answers

Answered by ragini8674
0

Step-by-step explanation:

may be this correct........

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Answered by satyachikkaraju2016
0

Step-by-step explanation:

Area of ∆PNQ = 1/2(base×height)

= 1/2(14×5)cm

= 1/2(70)cm

= 70/2cm

= 35cm

Area of ∆NQS = 1/2(base×height)

= 1/2(15+7.5)cm

= 1/2(22.5)cm

= 1/2(225/10)cm

= 1/2(45/2)cm

= 45/4cm

Area of ∆QRS = 1/2(base×height)cm

= 1/2(10×7.5)cm

= 1/2(10×75/10)cm

= 1/2(75)cm

= 75/2cm

So, Area of quadrilateral PRSN = Area of ∆PNQ + Area of ∆NQS + Area of ∆QRS

= 35/1cm+ 45/4cm+75/2cm

LCM of 1, 2 & 4 = 4

= (35×4)+(45×1)+(75×2)cm/4

= 140+45+150cm/4

= 335/4cm

That's what I think !

Excuse me if I did something wrong !

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