Question

A tower standing vertically on the ground.from a point on the ground which is 2m away from the foot of the tower.the angle of elevation of the top of the tower is found to be 45degree

Answer 1

Dear user you have not told what to find out. But still i will try to give you the answer.
Solution:-

Let the height of the tower be AB.
Now,
according to the question, it has told that that a point on the ground is 2 meter far from the foot of the tower.
So let the C be the point which is on the ground.
so, from this, we conclude that,
BC= 2 meter
Now the angle of elevation to the top of the tower is 45 degree.
so,
angle ACB = 45 degree
Now we have the required triangle that is ABC.
Now by taking angle C as ø, so base is BC which 2 meter and AB as height.
Now, in triangle ABC,

tan C = Perpendicular/ Hypotenuse
tan C = height of tower / base
tan 45 = AB/BC
1 = AB/BC. [tan 45 = 1]
BC = AB
AB = 2 meter
So, now AB becames equal to BC which 2 meter.
Hence, the height of the tower is 2 meter.