Question

a tower standing vertically on the gruond from a point which is 12meters away from the tower the angle of elevation of top of tower is 45degree find the hight of tower​

Answer 1

Step-by-step explanation:

A point on the ground which is 25 m away from the foot of the tower i. BC= 25 m

Let the height of the tower be x

The angle of elevation of the tower is found to be 45 degree.i.e.∠ACB=45°

In ΔABC

Using trigonometric ratios

$\tan(45) = 1 \div 12$

1= 1/12

Hence the height of the tower is 12 m

Answer 2

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