Question

A tower stands vertically on the ground from a point on the ground which is 20m away from the foot of the tower the angle of elevation of the top of the tower is found to be 60degree find the height of the tower

Answer 1

look

tan60= perpendicular / base
so √3= height of the tower/ distance from its foot
so,√3=H/20
so, H=20√3m

that is your answer

Answer 2

Given:

Distance of tower and a point=20 m

Angle of elevation,$\theta=60^{\circ}$

To find:

Height of tower

Solution:

In triangle

Let height of tower=h

Base=20 m

$\theta=60^{\circ}$

$tan\theta=\frac{Perpendicular\;side}{Base}$

Using the formula

$tan60=\frac{h}{20}$

$h=20tan60=20\times \sqrt{3}$

Using the value of

$tan60^{\circ}=\sqrt{3}$

$h=20\sqrt{3} m$

Hence, the height of tower=$20\sqrt{3} m$