Math, asked by manthakstut, 1 year ago

If d is the HCF of 45 and 27 , find x, y satisfying d = 27x+45y.

Answers

Answered by AlienRapper

5

HCF of 27 and 45 = 9
So, d = 9
X= -3
Y = 2
27x = -81
45y = 90
So, 27x + 45y = 9
I tried with trial and error method to solve this

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