Question

A tower stands vertically on the ground. From a point on the ground, 20 m away from the foot of the tower, the angle of elevation of the top the tower is 60°. What is the height of the tower?

Answer 1

Answer:

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Answer 2

Given :

A tower stands vertically on the ground. From a point on the ground, 20 m away from the foot of the tower, the angle of elevation of the top the tower is 60°.

To find:

Let AB be the tower standing vertically and O be the position of the observer we have now:

OA = 2m , <OAB = 90° and <AOB = 60°

Let AB = hm

Now in right angled triangle ΔAOB, we have,

AB/OA - tan 60° = √3

h/20 = √3

h = 20√3 = ( 20 * 1.732) = 34.64

Hence, the height of the pole is 34.64m.