Question

Construct a in which AB = 5 cm. altitude CD = 3 cm. Construct a similar to such that side of is 1.5 times that of the corresponding sides of .

Answer 1

Answer:

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Answer 2

To construct similar triangles, you have to calculate the length of each side 1.5 times more than given length.

Explanation:

Given:- AB = 5 cm  and CD = 3 cm.

So based on these two given information we have to construct the triangle ABC.

For Triangle ABC.

1. Draw a line segment AB = 5 cm. mark it A and B at the vertex.

2. Now Bisect the Line AB for midpoint D.

3. From D now mark a point C = 3 cm.  

Join points C and D to get the line segment CD = 3 cm.

Join Point A and C and also B and C. you will get a triangle ABC.

For Triangle  A’B’C’ you have to keep in mind that length of each side  is 1.5 times more than given length.

So A’B’ = 1.5 times of AB

= 1.5 times 5 cm

= 1.5 x 5 cm

= 15/10 x 5 = 7.5 cm.

As A’B’ = 1.5 time AB = 7.5 + 5 = 12.5 cm.

A’B’ = 12.5 cm.

Now for altitude we have C’D’ = 1.5 time CD

   = 1.5 times 3 cm.

   = 1.5/10 x 3

   = 4.5.

  C’D’ = 3 + 4.5 = 7.5.

Now following the above mentioned steps construct the second triangle A’B’C’.

So you have Triangle A’B’C’ which is  1.5 times triangle ABC.

(figure attached).