Question

A tower stands vertically on the ground from a point on the ground which is 25m away from the foot of the tower, the angle of elevation of the tower is found to be 45 degree. Find the height of the tower

Answer 1

Hope this will help you out....

Answer 2

Answer:

25m

Step-by-step explanation:

Refer the attached image

A point on the ground which is 25 m away from the foot of the tower i. BC= 25 m

Let the height of the tower be x

The angle of elevation of the tower is found to be 45 degree.i.e.∠ACB=45°

In ΔABC

Using trigonometric ratios

$tan\theta = \frac{Perpendicular}{Base}$

$tan 45 ^{\circ} = \frac{AB}{BC}$

$1= \frac{x}{25}$

$25=x$

Hence the height of the tower is 25 m.