Question

A tower stands vertically on the ground. From a point which is 15 meter away from the foot of the tower, the angle of elevation of the top of the tower is 45º. What is the height of the tower?

Answer 1

Answer:

15 m

Step-by-step explanation:

l\

l \

l \

l \

l_15_\

tan45° = 1 = height/15

So, Height = 15 m

Answer 2

Answer:

15m

Step-by-step explanation:

Let us assume a triangle ABC

Length of  the side CB = 15m  (Given)

Angle of elevation at the top of tower = 45° (Given)

Let the overall height of the tower AB be = H

In Δ ABC

∠ACB=45°, thus -

TanФ = AB/CB

Tan45 = AB/CB

1 = H/15

H = 15

Therefore the height of the tower is 15m