Question

a tower stands vertically on the ground from a point which is 15 M away from the foot of the tower the angle of elevation of the top of the tower is 45 degrees what is the height of the tower ​

Answer 1

Answer:

Step-by-step explanation:

The distance between the foot of the tower and the point on the ground is 15 .....

So apply the value of tan 45 and we get....

TAN 45= height of the tower ÷15 = opp side ÷ adj side

1=height of the tower ÷ 15

Height of the tower = 15 ......

HOPE this will help........

Answer 2

Given,

A tower stands vertically on the ground from a point which is 15 M away from the foot of the tower.

The angle of elevation of the top of the tower is 45°.

To find out,

The height of the tower.

Solution:

Let AB be the height of the tower = h units

C be the point of observation on the ground.

AC be the distance from observer to the foot of tower = 15 meters.

Now,

$In \: \triangle \: ABC \:$

$\tan45 \degree = \frac{opposite \: side \: to \: 45 \degree}{adjacent \: side \: to \: 45 \degree}$

$tan \: 45 \degree = \frac{AB}{AC}$

$1 = \frac{h}{15}$

$h = 15 \times 1$

$h = 15 \: meters$

Therefore the height of the tower is 15 meters.