Question

A toy car was moving at a speed of 20cm/s . After going a distance of 1 meter,the speed of that car is 50cm/s. How much the acceleration?

Answer 1

Answer:

0.105 m/s²

Explanation:

by 3rd equation of motion

given, v= 50 cm/s = 0.5 m/s ( final velocity)

          u= 20 cm/s = 0.2 m/s ( initial velocity)

          S = 1m  

               v² - u² =2aS

                 (0.5)² - (0.2)² = 2(1) a

                 0.25- 0.04 = 2a

                0.21= 2a

acceleration produced is 0.105 m/s²

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Answer 2

Answer

• Acceleration , a = 0.105 m/s²

Given

• A toy car was moving at a speed of 20 cm/s . After going a distance of 1 meter,the speed of that car is 50 cm/s

To Find

• Acceleration ,a

Solution

Initial speed , u = 20 cm/s = 0.2 m/s

Final speed , v = 50 cm/s = 0.5 m/s

Distance , s = 1 m

Acceleration , a = ? m/s²

Apply 3rd equation of motion .

⇒ v² - u² = 2as

⇒ 0.5² - 0.2² = 2a(1)

⇒ 0.25 - 0.04 = 2a

⇒ 0.21 = 2a

⇒ a = 0.105 m/s²