Question

a toy car was moving with a speed of 20cm /s it's speed become 50m/s after traversing a distance of 1m calculate the acceleration of the car​?



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Answer 1

Answer :-

Acceleration of the car is 1249.98 m/s² .

Explanation :-

We have :-

→ Initial velocity (u) = 20 cm/s

→ Final velocity (v) = 50 m/s

→ Distance travelled (s) = 1 m

To find :-

→ Acceleration (a) .

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Firstly, let's convert the unit of initial velocity of the toy car, from cm/s to m/s .

⇒ 1 cm/s = 0.01 m/s

⇒ 20 cm/s = 20(0.01)

⇒ 0.2 m/s

Now, let's calculate the acceleration of the car with the help of 3rd equation of motion .

v² - u² = 2as

⇒ (50)² - (0.2)² = 2(a)(1)

⇒ 2500 - 0.04 = 2a

⇒ 2499.96 = 2a

⇒ a = 2499.96/2

⇒ a = 1249.98 m/s²

Answer 2

G I V E N

• Initial velocity (u) = 20 cm/s = 0.2 m/s

• Final velocity (v) = 50 m/s

• Distance covered (s) = 1 m

T OㅤF I N D

• Acceleration of the toy car ?

S O L U T I O N

★ Using third eqⁿ of motion::

$\quad\odot\:\underline{\boxed{\sf{v^2 = u^2 + 2as}}}$

★ Putting all known values::

➝ㅤ (50)² = (0.2)² + 2(a)(1)

➝ㅤ 2a + 0.04 = 2500

➝ㅤ 2a = 2500 - 0.004

➝ㅤ 2a = 2499.96

➝ㅤ a = 2499.96/2

★ After cancelling 2499.96 with 2, we get::

➝ㅤ Acceleration (a) = 1249.98 m/s²

∴ Hence, acceleration of the toy car is ㅤㅤ1249.98 m/s².

M O R EㅤT OㅤK N O W

★ Three equations of motion::

• v = u + at

• s = ut + ½ at²

• v² = u² + 2asㅤㅤㅤ[Used above]

★ Some important definitions::

• Acceleration

Acceleration is the process where velocity changes. Since, velocity is the speed and it has some direction. So, change of velocity is considered as acceleration.

• Initial velocity

Initial velocity is the velocity of the object before the effect of acceleration.

• Final velocity

After the effect of the acceleration, velocity of the object changes, the new velocity gained by the object is known as final velocity.

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