Question

A toy car was moving with a speed of 20cm/s. Its speed became 50m/s after traversing a distance of 1m. Calculate the acceleration of the car.
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Answer 1

Answer:

10.5m/s square

Explanation:

initial velocity= 20cm/s

final velocity=50m/s

distance=1m =100 cm

by third rule of motion

v square= u square +2as

so, 50 sq. = 20 sq. + 2 a (100)

2500. =. 400 + 200 a

2500-400=200a

2100 = 200a

2100/200= a

10.5m/s sq. =a

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Answer 2

Answer:

1050m/s²

Explanation:

car was moving with speed 20m/s

i.e u=20m/s

after traveling 1m the speed was 50m/s

i.e v= 50m/s

therefore using the kinematics equation we get

v²=u²+2as

therefore 2500=400+2a1

by solving we get

a=1050m/s²