A toy car weight 1.5kg is moving along the horizontal surface with a constant velocity 0.2m/s. The coefficient kinetic friction between the car and meveS is 0.17. What is the magnitude of Force maintain Constant velocity?What force will be change the velocity 2.6m/s in 2 second
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Answer:
F = 4.29 N
Explanation:
Mass = 1.5kg
V1 = 0.2 m/s
v2 = 2.6 m/s
Mk = 0.17
t = 2 sec
a = V2-V1/t
= 2.6-0.2 / 2 = 2.4/2 = 1.2m/s^2
N = mg
= 1.5*9.8 = 14.7 N
fk = MkN
= 0.17*14.7
= 2.49 N
V2-V1/t = F-fk/m
1.2 = F-2.49/1.5
1.2*1.5 = F-2.49
1.8 = F-2.49
F = 1.8+2.49
F = 4.29 N
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