Question

A toy cart at the end of a string 0.70 m long moves in a circle at a table. The cart has a mass of 2.0 kg and the string has a breaking point of 40 N. Calculate the maximum speed the cart can attain without breaking the string.​

Answer 1

Answer:

3.7

Explanation:

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Answer 2

$Given,$

$R\:=\:0.70m \: \: \: \: \: \: M\:=\:2kg \: \: \: \: \: \: \: \: \: \: Tensile\: strength\:=\:40n$

$\frac{ {mv}^{2} }{r \: } = \frac{ {2}^{2} }{0.70}$

$\frac{ {2}^{2} }{0.70} = 40$

$v \: = \: \sqrt{ \frac{400 \times 0.70}{0.9} }$

$v \: = \: \sqrt{\frac{280}{0.9} }$

$v \: = \: \sqrt{311.111}$

$v \: = \: 17.638 \: m etre\: per \: second$