a toy in the form of a cone mounted on a hemisphere with the same radius . the radius of a bade 9f a conical portion is 3 cm and its height is 4cm. find the TSA of the toy
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Solution=
Radius of conical part=3cm
Radius of hemispherical part=3cm
Height of conical part=4cm
Therefore, height of hemispherical part=4-3=1cm
T.S.A of the toy=C.S.A of conical part + C.S.A of hemispherical part
πrl+2πr²(formulas)
Now, we have to find l(slant height)
l=√h²+r²
l=√(4)²+(3)²
l=√16+9
l=√25
l=5cm
now, putting value on formulas
πrl+2πr²
πr(l+2r)
π(3)[5+2(3)]
3π×5+6
3π×11
33π
33×22/7
103.71cm²
Therefore, Total surface area of toy is 103.71cm²
Radius of conical part=3cm
Radius of hemispherical part=3cm
Height of conical part=4cm
Therefore, height of hemispherical part=4-3=1cm
T.S.A of the toy=C.S.A of conical part + C.S.A of hemispherical part
πrl+2πr²(formulas)
Now, we have to find l(slant height)
l=√h²+r²
l=√(4)²+(3)²
l=√16+9
l=√25
l=5cm
now, putting value on formulas
πrl+2πr²
πr(l+2r)
π(3)[5+2(3)]
3π×5+6
3π×11
33π
33×22/7
103.71cm²
Therefore, Total surface area of toy is 103.71cm²
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