A toy is in the form of a cone mounted on a hemisphere. The diameter of the base and the height of the cone are 6 cm and 4 cm respectively. Determine the surface area of the toy. [use π = 3.14]
Answers
Answer:
103.62cm^2.
Step-by-step explanation:
We get from the question that for cone -
The formulae of the slant height of the cone is, l = √(r²+h²).
l = √3²+4².
l = √9+16.
l = 5.
Also, the formulae of the lateral surface area of the cone = πrl.
=3.14 × 3 × 5
=3.14 × 15
On solving we will get 47.10 cm^2.
Again for the Hemisphere we have-
Lateral surface area of hemisphere = 2πr^2.
=2 × 3.14 × 3^2.
=2 × 3.14 × 9.
=18 × 3.14.
On solving we will get 56.52 cm^2.
So, the surface area of the toy is the lateral surface area of cone + lateral surface area of hemisphere.
=47.10 + 56.52.
=103.62cm^2.
Hence, the total surface area of toy from the above solution will be= 103.62cm^2.
Answer:
Step-by-step explanation:
Height of the cone = 4 cm
Diameter of the come = 6 cm.
Thus, radius of the cone = 6/2 =3 cm.
Slant height = l of the cone = √r² + h²
= √3² + 4²
= √ 9+16
= √25
= 5
Surface area of cone = πrl
= 3.14 × 3 × 5
= 47.1
Surface area of hemisphere = 2πr²
= 2 × 3.14 × (3)²
= 56.52
Total surface area of toy = Area of cone + Area of hemisphere
= 47.1 + 56.52
= 103.62
Thus, the surface area of toy is - 103.62 cm².