Math, asked by danducharansai, 11 months ago

A toy is in the form of a cone of radius r cm mounted on a hemisphere of the same radius the total height of the toy is (r+h)cm then the volume of toy is ?​

Answers

Answered by mrdhakad121
8

Step-by-step explanation:

answer is 1/3π^2[h+1/3r]

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Answered by FelisFelis
12

The volume of the toy is \frac{1}{3}\pi r^2(h+ 2r)

Step-by-step explanation:

Consider the provided information.

The radius of toy is r cm and mounted on a hemisphere of same radius.

The total height of the toy is (r+h) cm

Volume of the toy = Volume of cone + Volume of hemisphere

Volume of the toy =  \frac{1}{3}\pi r^2h+ \frac{2}{3}\pi r^3

Volume of the toy = \frac{1}{3}\pi r^2(h+ 2r)

Hence, the volume of the toy is \frac{1}{3}\pi r^2(h+ 2r)

#Learn more

A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius the total height of the tower is 15.5 cm find the total surface area of the toy

https://brainly.in/question/3212115

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