Question

A toy is in the Shape of a cylender
with tow equal
cones stuck to each other of
its ends. The length of entire
solid is 30cm and diameter of cylender and cones 10.5cm
and the length of the
calender is 14cm. find its
surface area.​

Answer 1

Answer:

total surface area = 726 cm²

Step-by-step explanation:

total length = 30 cm

r = 5.25 cm

height of cylinder = 14 cm

length of 2 cones = 30-14 = 16 cm

length of each cones = 16/2 = 8 cm

h = 8

r = 5.25

R = 5.25

H = 14

l = √r²+h²

l = √5.25²+8²

l = √27.5625+64

l= √91.5625

l = 9.56888 = 9.57 cm approx

now total surface area = 2πRH+2πrl

                                      = 2π(RH+rl)

                                      = 2*22/7*5.25(14+8)

                                      = 44*5.25*22/7

                                      = 44*22*3/4

                                      = 11*66

                                      = 726 cm²

DO MARK IT AS BRAINLIEST.

Answer 2

The surface area of the cylinder is 726 cm².

Explanation:

Given: The length of entire solid = 30 cm

Diameter of cylinder and cone = 10.5 cm, r = 5.25 cm

Length of cylinder, H = 14 cm

Length of 2 cones = Length of entire solid - Length of cylinder = 30 - 14 = 16 cm

Length of each cones = 16 ÷ 2 = 8 cm

Height of the cone, h = 8 cm.

Surface area = ?

Formula: Total surface area of the cylinder = 2πRH + 2πrl

Substituting the values, we get the surface area value as

Surface area = 2 x π x 5.25 x 14 + 2 x π x 5.25 x 8

= 2π(5.25 x 14 + 5.25 x 8)

= 2π(73.5 + 42)

= 2π(115.5)

= $2\times\frac{22}{7}\times 115.5$

= 2 x 22 x 16.5

= 726 cm²

The surface area is 726 cm².

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