A toy is in the shape of a right circular cylinder with a hemisphere on one end and a cone on the other. The radius and height of cylindrical part are 5cm & 13 cm respectively.The radii of hemisphere and conical parts are the same as that of cylindrical part .calculate the surface area of toy of the height of conical part is 12 cm .draw figure
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Heya !!
Here's your answer..
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Radius of cylinder = Radius of cone = Radius of hemi sphere = 5cm
Height of cylinder ( h1 ) = 13cm
Height of cone ( h2 ) = 12cm
Slant height of cone ( l )² = r² + h2²
l² = 5² + 12²
l² = 25 + 144
l = √169
l = 13cm
Surface area of figure = C.S.A of cone + C.S.A of cylinder + C.S.A of H.S
= πrl + 2πrh1 + 2πr²
= πr ( l + 2h1 + 2r )
= 22/7 × 5 [ 13 + 2(13) + 2(5) ]
= 22/7 × 5 [ 13 + 26 + 10 ]
= 22/7 × 5 [ 49 ]
= 22 × 5 × 7
= 110 × 7
= 770 cm²
_________________________
Hope it helps..
Thanks :)
Here's your answer..
___________________
Radius of cylinder = Radius of cone = Radius of hemi sphere = 5cm
Height of cylinder ( h1 ) = 13cm
Height of cone ( h2 ) = 12cm
Slant height of cone ( l )² = r² + h2²
l² = 5² + 12²
l² = 25 + 144
l = √169
l = 13cm
Surface area of figure = C.S.A of cone + C.S.A of cylinder + C.S.A of H.S
= πrl + 2πrh1 + 2πr²
= πr ( l + 2h1 + 2r )
= 22/7 × 5 [ 13 + 2(13) + 2(5) ]
= 22/7 × 5 [ 13 + 26 + 10 ]
= 22/7 × 5 [ 49 ]
= 22 × 5 × 7
= 110 × 7
= 770 cm²
_________________________
Hope it helps..
Thanks :)
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