Question

a trader bought a number of articles for 900 and 5 were damage and he sold each of the rest at to more than what he paid for it was getting a profit of 80 on whole transaction find the number of articles were bought​

Answer 1

Step-by-step explanation:

Let the total number of articles be n.

Let the value of one article be a.

Given that trader bought n articles for Rs900.

So that n×a=900 and a= 900/ n

Also given that five of them were damaged, he sold the remaining articles for Rs. 2 extra and he also got a Rs. 80 profit.

So that the equation would be (n−5)×(a+2)=900+80

⇒ na – 5a + 2n – 10 = 980.

⇒ 900 – 5 × 900÷ n + 2n = 990 [.: na = 900 and a = 900÷ n]

⇒ 2n– 4500 ÷ n = 90

⇒ n – 2250÷ n = 45

⇒ n² – 2250 = 45n

⇒ n² – 45n -2250 = 0

⇒ n² – 75 n + 30n– 2250 = 0

⇒ n(n−75)+30(n−75)=0

⇒ (n−75)(n+30)=0

⇒ n=75 or −30

Since n is the number of goods, it is always positive.

Hence, number of articles he bought was 75

hope it's helpful for you .

if you like my answers ,then definitely like and comment it .