A trader bought a number of articles for Rs 900. 5 articles were found damaged.He sold each of the remaining articles at Rs.80 in the whole transaction. Find the number of articles he bought?
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Total rupees =900
Damaged articles=5
Price of each article=80
Therefore,price of articles sold=5x80
=400
Rupees left =900-400=500
No. Of articles=500/80=50/8
@Marcia Royal
Damaged articles=5
Price of each article=80
Therefore,price of articles sold=5x80
=400
Rupees left =900-400=500
No. Of articles=500/80=50/8
@Marcia Royal
Answered by
1
let the total no of aarticles be n
let the value of one article ne a
given:
na=900
a=900/n
(n-5)*(a+2)=980
na-5a+2n=990
900-5(900/n)+2n=990
2n-4500/n=90
n2-2250=45n
n2-45-2250=0
n(n-75)30(n-75)
(n+30) (n-75)
n=-30 n=75
sine the no of arrticles cannot be in negative
the answer is 75
Step-by-step explanation:
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