Question

A trader fixes the price of a radio at 20% above cost price. if he allows a discount of 5% on the list price , then his profit percentage is : ?​

Answer 1

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Answer 2

Answer:

$\huge\bf\underline\red{Solution:}$

$\bf\brown{Let\:the\:cost\:price\:be\:x}$

$\bf\green{List\:Price = ( 1 + \frac{R}{100}) }$

$\bf{Net\:Selling\:Price = List\:Price({1- \frac{d}{100} })......(i) }$

$\bf\blue{Let\:the\: profit\:percentage=r}$

then,

$\bf{Net\:Selling\:Price = cost\:Price({1+ \frac{r}{100} }).....(ii)}$

From (i) and (ii),

$\bf\green{List\:Price ( 1 - \frac{d}{100} )=Cost\:Price ( 1 + \frac{r}{100} )}$

$\bf\pink{\implies List\:price = Cost\: price \frac{100+r}{100-d} }.....(iii)$

$\bf\orange{\implies x(1+ \frac{R}{100} ) = x( \frac{100+r}{100-d} )}$

$\bf\blue{\implies 1 + \frac{20}{100} = \frac{100+r}{100-5} }$

$\bf\purple{\implies 1 + \frac{1}{5} = \frac{100+r}{95} }$

$\bf\blue{\implies \frac{6}{5} \times 95 =100+r }$

$\bf\red{\implies 114 =100+r }$

$\bf\green{\because r =114 - 100 }$

$\bf\green{\implies r =14 }$

The Profit Percentage be 14%.