Math, asked by kirankalyan, 6 months ago


A trader has 44 kg of rice, a part of which he sells at 14% profit and the rest at 8% loss. On the whole, his loss is 4%. What is the quantity sold at 8%
loss?​

Answers

Answered by Bhawana861
0

Answer:

Step-by-step explanation:

CP=44kg

P% of one part =14%

L% of other part =8%

Total loss% =4%

SP at 8%=?

now,

CP-x=14%

44-14/100=x

4,400-14=100x

4,386=100x

x=43.86

now,

l%=CP-SP/CP*100%

4%=44-SP/44*100%

176=44-100SP

100SP=-132

SP=Rs.0.75

now,

SP at 8% loss=?

l%=CP-SP/CP*100%

8%=CP-0.75/CP*100%

8CP=100CP-75

75=92CP

CP=Rs.0.81........

Answered by PoojaBurra
0

The quantity sold at loss is 36 kg.

Given - Total quantity, loss, profit and overall loss

Find - Quantity sold at 8% loss

Solution - Let the quantity of rice sold at loss be x. So, the quantity of rice sold at profit will be (44-x).

Now, forming the relation as -

Quantity of loss*loss% + Quantity at profit*profit% = total quantity*total loss%

Keep the values in formula

x*(-8) + (44-x)*14 = -44*4

-8x + 616 - 14x = -176

616 + 176 = 14x + 8x

792 = 22x

x = 792/22

x = 36

Hence, 36 kg rice was sold at 8% loss.

#spj3

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