Question

A trader offers two successive discounts of 10 and 7 % on an article whose Marked price is 2400 find its selling price

Answer 1

Answer:

Given marked price = Rs. 4600

First discount= 10%

Cost of article after first discount = Market price - discount

4600-10\% \text{ of } 4600= 4600-\dfrac{10}{100} =4600- 460 =Rs. 41404600−10% of 4600=4600−

100

10

=4600−460=Rs.4140

Second discount = 8%

therefore selling price= 4140 - second discount

4140-8\% \text { of } 4140 =4140 -\dfrac{8}{100} \times 4140=4140- 8\times 41.4= Rs. 3808.84140−8% of 4140=4140−

100

8

×4140=4140−8×41.4=Rs.3808.8

Hence, the selling price of article after two successive discount is Rs. 3808.8

Step-by-step explanation:

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Answer 2

Answer:

2400*7/100*10/100

24*7/10

16.8