Question

A trader was moving along the road selling eggs.An idler who don't have any work to do ,started get the trader in the wordy duel. This grew into a fight,he pulled the baskets of eggs and dashed on the floor.The eggs broke. The trader request the panchayat to ask the idler to pay for the broken eggs.The panchayat asked the traderhow many eggs werer broken. He gave the following response: If counted in pairs,one will remain; If counted in threes,two will remain; If counted in fours,three will remain; If counted in fives,four will remain; If counted in sixes,five will remain; If counted in sevens,nothing will left; My basket cannot accomodate more than 150 eggs. FIND HOW MANY EGGS WERE THERE BROKEN?

Answer 1

2/119=1,3/119=2,4/119=3,5/119=4,6/119=5,7/119=0

Answer 2

Hey Goanna, here is your Answer:--

Let eggs=x

When divided by 2,3,4,5 and 6, the remainder is always one less than the divisor

Thus, x is one less than LCM(2,3,4,5,6) OR one less than a multiple of the same.

Thus, x is one less than LCM(2,3,4,5,6) OR one less than a multiple of the same.

LCM=60

now,

x= (60-1) OR (120-1) OR (180-1)

60-1= 59

NOT divisible by 7

120-1=119

Maybe x= 119

180-1= 179

Cannot be over 150.

We can safely conclude that x= 119

The trader was carrying 119 eggs.