Question

a train 200 meters long was moving ot the rate of 40 kmph .in how mNY SECOUND WILL CROSS a man standing near the railway line

Answer 1

Distance = 200m = 200 / 1000
Speed = 40 km/h 
Time = Distance / Speed
→ (200 ÷ 1000) ÷ 40 
→ 0.2 ÷ 40 
→ 0.005 hr = 18s 

Answer 2

Answer:

In 18 sec, it will cross a man standing near the railway line will.

Explanation:

Given that,

Distance D = 200 m

Speed $v =40\ km/h=40\times\dfrac{5}{18}= 11.11\ m/s$

The distance is the product of the speed of the train and time.

$D = v\times t$

We need to calculate the time

$t = \dfrac{D}{v}$

$t =\dfrac{200}{11.11}$

$t =18\ sec$

Hence, In 18 sec, it will cross a man standing near the railway line will.