Question

A train accelarte from 36km/h to54km/h in 10 what is accelaration ?and the distance travvelled by train

Answer 1

$36 \times \frac{5}{18} = {10ms}^{ - 1} \\ 54 \times \frac{5}{18} = {15ms}^{ - 1} \\ a = \frac{v - u}{t} \\ a = \frac{15 - 10}{10} \\ a = {0.5ms}^{ - 2}$