a train accelerate from 36 km/h to 54km/h in 10sec (1) the distance travelled by car.
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velocity(1)= 36 km/h
velocity(2)= 54 km/h
Total velocity= v1+v2
=(36+54) km/h
= 90 km/h= 90×5/18 m/s= 25 m/s
Time= 10 s
Distance= total velocity×time
= 25 m/s × 10 s
= 250 m or = 250×1/1000 km = 0.25 km
Thus, the distance covered is 0.25 km or 250 m.
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