Question

A train accelerate from 36km/h to 54km/h in 10 sec find acceleration and distance travelled by the train

Answer 1

distance travelled by train is 125 m

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Answer 2

u=36km/h=10m/s
v=54km/h=15m/s
t=10s
Now,
Acceleration = v-u/t = 15-10/10 = 0.5 m/s^2
Now,
Distance= u*t + at^2/2 = 10*10 + 0.5*10*10/2 = 100 + 25 = 125m.
So......
a= 0.5m/s^2 and
s= 125m.