Question

A train accelerated from 10km/hr to 40km/hr in 2 minutes. How much distance does it cover in this period? Assume that the tracks are straight?

Answer 1

u=10km/h

v=40km/h

t=2min=1/30h

S=ut+1/2at^2

=10×1/30+(1/2)×(v-u/2)×(1/30)^2

=1/3+(1/2)×(30/2)×(1/900)

=1/3+1/120

=41/102 km/h^2

Answer 2

Old speed = 10kmph

New speed= 40kmph

increase in speed= 40kmph-10kmph

= 30kmph

distance travelled by it in 1 hour=40km

dis. travelled by it in 1 sec.= 40×5÷18

= 11.11m

2 minutes= 120 secs .

distance travelled in 1 sec. = 11.11m

distance travelled in 2 min.=11.11×120

=1333.33km

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