Question

Solve x and y.
x/a +y/b=a+b,x/a^2+y/b^2=2.

Answer 1

Answer:

Form the eq.

x/a +y/b=a+b. ... ( 1)

x/a^2+y/b^2=2. ....(2)

On multiple eq.1 by b and eq.2 by b^2 also on subtracting ,we get,

bc/a -b^2x/a^2 = ab+b^2-2b^2

Or (ab -b^2/a^2)x =ab-b^2

Or x=(ab -b^2)a^2/ab-b^2 = a^2

Now on subtracting x=a^2 in eq.1 .

We get,

a^2/a +y/b =a +b

Or y/b=a+b-a=b

Or y=b^2

Hence x=a^2 and y =b^2.

Answer 2

Answer:

Form the eq.

x/a +y/b=a+b. ... ( 1)

x/a^2+y/b^2=2. ....(2)

On multiple eq.1 by b and eq.2 by b^2 also on subtracting ,we get,

bc/a -b^2x/a^2 = ab+b^2-2b^2

Or (ab -b^2/a^2)x =ab-b^2

Or x=(ab -b^2)a^2/ab-b^2 = a^2

Now on subtracting x=a^2 in eq.1 .

We get,

a^2/a +y/b =a +b

Or y/b=a+b-a=b

Or y=b^2