a train accelerates from 10 km per hour to 40 km per hour in 2 minutes how much distance does it cover in this period assume that the tracks are straight
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initial velocity,u=10km/h
final velocity,v=40km/h
time,t=2min=1/30h
since , S=ut+1/2at^2
=10×1/30+(1/2)×(v-u/2)×(1/30)^2
=1/3+(1/2)×(30/2)×(1/900)
=1/3+1/120
=41/102 km/h^2
final velocity,v=40km/h
time,t=2min=1/30h
since , S=ut+1/2at^2
=10×1/30+(1/2)×(v-u/2)×(1/30)^2
=1/3+(1/2)×(30/2)×(1/900)
=1/3+1/120
=41/102 km/h^2
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Answer:
the answer for question mentioned above is 833.33m
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