Question

a train accelerates from 10ms^-1 to 20ms^-1 in 20 sec. find the distance travelled by it

Answer 1

Answer:

300 m

Explanation:

here, we have to use equations of motion.

1. v=u+at
2. v2=u2+2as

where, v=final velocity(20m/s)

u=initial velocity(10m/s)

a=accleration

t=time(20 sec)

s=distance covered

1. a=(v-u)/t

=(20-10)/20

=0.5m/s2

2. s=(v2-u2)/2a

=(400-100)/1

=300 m