a train accelerates from 20 km per hour to 80 km per hour in 4 minutes how much distance does it cover in this period .assume that the tracks are same
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GIVEN:
u=20 km/h
v=80km/h
t=4min
Converting the give data to m/s
u=20×5÷18=5.5m/s
v=80×5÷18=22.2m/s
t=4×60=240s
So, a=v-u÷t
a=22.2-5.5÷240
=22.4m/s.s
Distance=
s=ut+1÷2at.t
=5.5*240s+1÷2 *22.4*240*240
=646,440ms
u=20 km/h
v=80km/h
t=4min
Converting the give data to m/s
u=20×5÷18=5.5m/s
v=80×5÷18=22.2m/s
t=4×60=240s
So, a=v-u÷t
a=22.2-5.5÷240
=22.4m/s.s
Distance=
s=ut+1÷2at.t
=5.5*240s+1÷2 *22.4*240*240
=646,440ms
Answered by
1
64,440ms.00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000........................................infinity
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