Question

A train accelerates from 36 km/h to 54 km/h in 10 sec. Find (a) Acceleration (b) Distance travelled by car.

Answer 1

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Answer 2

A)u=10m/s

v=15m/s

t=10 sec

a=(v-u)/t

=(15-10)÷10

=0.5m/s^2

B)s=ut+1/2at^2

s=10×10+1/2(0.5×100)^2

=100+1/2×50

=100+25

=125m