Question

A train accelerates from 36 km/h to 54 km/h in 10 sec.
(i) Acceleration
(ii) The distance travelled by car.

Answer 1

A = V-U/t

=54-36/10
=1.8.m/s^2


I think u understood the terms.


S=ut+at^2/2

=36×10+1.8×100/2
=360+90
=430m.

please let me know about the answer. if u like it then give me the brainliest answer.

Answer 2

Answer:

A = V-U/t

=54-36/10

=1.8.m/s^2

I think u understood the terms.

S=ut+at^2/2

=36×10+1.8×100/2

=360+90

=430m.

please let me know about the answer. if u like it then give me the brainliest answer.