A train accelerates from 36 km/h to 54 km/h in 10 sec.(i) Acceleration(ii) The distance travelled by car.
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Explanation:
(i) a = (v-u)/t
= (54-36)/10
= 18/10 = 1.8m/s²
(ii) s = ut+1/2at²
= (36×10)+1/2×1.8×10²
= 360 + 1/2×1.8×100 = 360 + 90
= 450m
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