Question

A train accelerates from 36 km/h to 54 km/h in 10 sec.

(i) Acceleration

(ii) The distance travelled by car.
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Answer 1

SOLUTION ☺️
______________

GIVEN,_Initial velocity= 36km/h=36x5/18=10m/s

Final velocity =54km/h=54x5/18=15m/s

Time =10sec

Acceleration = v-u/ t

=15-10/10=5/10=1/2=0.5 m/s2

Distance =s=?

From second equation of motion:

S=ut +1/2 at^2

=10*10+1/2*0.5*10*10

=100+25

=125m

So distance travelled is 125m

MARK BRAINLIEST✓

Answer 2

Question :

A train accelerates from 36 km/h to 54 km/h in 10 sec.

(i) Acceleration

(ii) The distance travelled by car.


Answer :

a) Acceleration is given by

So, a= ∆v/∆t

So a=.2 m/s2

b) Distance is given by

1 /2