Question

a train accelerates from 36 km /h to 54 km/ h in 10 seconds ?calculate the acceleration​

Answer 1

$\Large{\blue{\sf{ɢɪᴠᴇɴ:}}}$

• Initial Velocity (U) = 36kmph
• Final Velocity (V) = 54kmph
• Time Taken = 10 Seconds

$\huge{\sf{ꜱᴏʟᴜᴛɪᴏɴ:}}$

U = 36kmph

→ 36×5/18

→ 2×5

→ 10 m/s

___________

V = 54kmph

→ 54×5/18

→ 3×5

→ 15 m/s

___________

$\boxed{\sf{☆\; Acceleration (a) = \frac{Final\; Velocity (V) - Initial\; Velocity(U)}{Time\;Take}}}$

$→\;{\frac{15-10}{10}}$

$→\;{\frac{5}{10}}$

$→\;{\bf{0.5}}$

• Acceleration = $\Large\red{\sf{0.5\;m/s²}}$

$\Large{✓}$

Hope It Helps You ✌️

Answer 2

$\huge\bf{Anѕwєr}$

Initial Velocity = 36kmph

➪ 36×$\frac{5}{18}$

➪ 2×5

➪ 10 m/s

Final Velocity = 54kmph

➪ 54×5/18

➪ 3×5

➪ 15 m/s

$\sf{Acceleration (a) = \frac{Final\; Velocity - Initial\; Velocity}{Time\;Take}}$

➪ ${\frac{15-10}{10}}$

➪ ${\frac{5}{10}}$

➪ $\sf{0.5}$

$\Large\purple{\sf{Acceleration = \;0.5\;m/s²}}$