Question

a train accelerates from 36 km per hour to 54 km per hour in 10 seconds calculate acceleration and the distance travelled by car and

Answer 1

hey dear
here is your answer

given data :

initial velocity (u) = 36 km/hr or 10 m/s

final velocity (v) = 54 km/hr or 15 m/s

time (t) = 10 seconds

to find : acceleration and distance

here we go

solution : for acceleration

by using 1st equation of motion

v = u+at

15 = 10+10a

10a = 5

a = 0.5 m/s²

solution : for distance

by using third equation of motion

v² = u²+2as

(15)² = (10)²+2*0.5*s

1s = 225-100

s = 125 meter

hope it helps :)

Answer 2

Given that
U = 36 km/h
V = 54 km/h
T = 10 sec or 1/6 h
A = v - u / t
= 54 - 36 / 1/6
= 18 × 6
= 108 km/h^2
S = ut + 1/2 at^2
= 36 × 1/6 + 1/2 × 108 × (1/6^2)
= 6 + 54 × 1/36
= 6 + 1.5
= 7.5 km