Question

A train accelerates from 36 km per hour to 54 km per hour in 10 second.
1) acceleration
2) the distance travelled by car​

Answer 1

Answer:

Given:

Initial velocity= 36km/h=36x5/18=10m/s

Final velocity =54km/h=54x5/18=15m/s

Time =10sec

Acceleration = v-u/ t

=15-10/10=5/10=1/2=0.5 m/s2

Distance =s=?

From second equation of motion:

S=ut +1/2 at^2

=10*10+1/2*0.5*10*10

=100+25

=125m

So distance travelled is 125m

Explanation:

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Answer 2

Given :-

A train accelerates from 36 km per hour to 54 km per hour in 10 second.

To Find :-

1) acceleration

2) the distance traveled by car​

Solution :-

We know that

1 km/h = 5/18 m/s

36 km/h = 36 × 5/18 = 10 m/s

54 km/h = 54 × 5/18 = 15 m/s

Now

①

We know that

a = (v - u)/t

a = (15 - 10)/10

a = 5/10

a = 0.5 m/s²

②

We know that

v² - u² = 2as

(15)² - (10)² = 2(0.5)(s)

225 - 100 = s

125 = s