Question

a train accelerates from 36km/h to 72km/h on covering a distance of 50 m.Calculate the acceleration of the train and time taken to cover the distance 50 m

Answer 1

v=72kmph=72*5/18=20m/s
u=36kmph=36*5/18=10m/s
v²-u²=2as

20²-10²=2*a*50

300=100a

a=3m/s²

v=u+at

20=10+3t

10=3t

t =10/3 seconds


ANSWER
1)TIME TAKEN=10/3seconds

2)ACCELERATION=3m/s²