Question

a train accelerates uniformly from 36km/hr to 72km/hr in 20 secs. find the distance travelled
please answer as quickly as possible

Answer 1

Answer:

The distance travelled is 10m or 0.01km.

Step-by-step explanation:

Given: u = 36 km/hr = 10m/s

           v = 72 km/hr = 20m/s

             t = 20 seconds

w.k.t., Acceleration, a = $\frac{v-u}{t}$

⇒ a = $\frac{(20-10)}{20}$

⇒ a = 0.5m/s²

∵The acceleration is constant. ∴According to Third equation of motion

v-u = 2as

⇒ 20-10 = 2×0.5×s

⇒ 10 = 1.0×s

⇒ s = 10m = 0.01km

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