Question

a train accelerates uniformly from 38km/hr to 72km/hr in 20s. Find the distance travelled.[3Marks]
plzz help me out
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Answer 1

Answer:

v=72km/hr=20m/s

u=38km/hr=10m/s

t=20s

v=u+at

20=10+a*20

a=0.5m/s^2

distance s=ut+1/2at²

=10*20+1/2*0.5*20²

=300m

Answer 2

V = 72*5/18 = 20m/s

U = 38*5/18 = 95/9 m/s

t = 20 sec

v = u + at

putting values ,

20 = 95/9 +20a

85/9 = 20a

a = 17/36

D = ut+1/2at²

= 95/9*20+1/2*17/36*20²

= 324.44 m (Ans)